Helical lead Tree Vmc PC2100

[Chris Kozell]

Any one run into this when programing a helical entry on on Tree machine? The control errors and reads "an axis helical lead is required for a helical interpolation".

 

Here is a small seg where the control errors at block#4065

N4062 G3 X2.9354 Y-2.0299 I2.9354 J-1.944

N4063 G1 X4.9611 Z-.2418

N4064 G3 X4.9875 Y-2.0247 I4.9611 J-1.9611

N4065 X5.0098 Y-2.0098 Z-.2419 I4.9611 J-1.9611

N4066 X5.0247 Y-1.9875 I4.9611 J-1.9611

N4067 X5.0299 Y-1.9611 I4.9611 J-1.9611

From what the book says the helical lead is the feed distance that the third axis moves per 360 deg of circular motion of the axis.

Any ideas out there?

[Slepydremr]

Is it an acramatic controller?

 

I think you have to have a k value that is your helical lead..

 

Like if you're going .250 deep in 2 full revs

 

K.125

 

It's been a while since I looked at an acramatic but I'm pretty sure it's a K.

 

However in your case you're code put out a .0001 difference. You may have to do something with your filter. Or check your geometry.

[Chris Kozell]

Its a Acramatic 2100 mc control. From what i see in the code it outputs one full rev per line.So what ever the z value is the k should be also?

[Guest]

Chris,

 

The z value should be the incremental move from where the move begins to where it ends. It will function in the same was as the I's and J's. Incremental along the axis.

 

I am not familiar with this control in particular but it does make a whole lot of sense.

[Slepydremr]

quote:

---

So what ever the z value is the k should be also?

---

Sort of yes on the 2100 control your on your line

 

N4065 X5.0098 Y-2.0098 Z-.2419 I4.9611 J-1.9611

 

I think you should have a K-.0001.

 

I use to program 2100's but I can't remember too well the last time I did helical interpolation.

[Guest CNC Apps Guy 1]

You've got mail.

[Chris Kozell]

thanks guys, Im going to go try it on the machine.

[Slepydremr]

Oops sorry, I just checked my old acramtic post and this is what it puts out.

 

code:

---

N124G00 G90 X0. Y0. Z10.

N126G0G90X.75Y0.

N128Z.1

N130G94G1Z0.F6.42

N132G3X-.75Z-.05I-.75J0.K.1F24.45

N134X.75Z-.1I.75J0.K.1

N136X-.75Z-.15I-.75J0.K.1

N138X.75Z-.2I.75J0.K.1

---

it looks like the k is always positive.

 

Sorry.

[ak762]

This segment of post always help me with helical and circular interpolation

Hope it help to discover from where you got wrong code

 

*************************************************

 

pcirout #Output to NC of circular interpolation

if abs(zinc) <> zero & plane = 0, #Doing a Helical move

[

if arcoutput <> zero, arcoutput = zero #Set for I,J,K arc format

kpitch = (360 / ABS(sweep)) * ABS(zinc) #Calc. the helix pitch

]

else, kpitch = zero

if full_arc_flg = 1,

 

pcan1, pbld, n, `sgfeed, sgplane, sgcode, sgabsinc, pccdia,

pfxout, pfyout, pzout, pcout, parc, [if kpitch > zero, *kpitch],

feed, strcantext, scoolant, e

 

 

else, pcan1, pbld, n, `sgfeed, sgplane, sgcode, sgabsinc, pccdia,

pxout, pyout, pzout, pcout, parc, [if kpitch > zero, *kpitch],

feed, strcantext, scoolant, e

*************************************************