DEG TO ROTATE FOR HELIX

[HEAVY METAL]

i got a roll that is 36 in long 12 dia. the info they have given me is 3.125 lead helix in 36 inches. what i.m trying to figure out is how many deg. to rotate to get 3.125 lead. i figured how many inches per deg off the circumf. then took 3.125 / by that and cam up witj about 29 deg. doesn't seem right though.

[LNDCAD]

I might not understand your layout correctly, but I believe that if the lead is 3.125", then the form on the roll should "feed" 3.125" per revolution of the roll. Along the 36" roll will be approximately (just under)12 full turns. I am not sure what else they could mean by a 3.125 lead helix in 36 inches. You only need to use the circumference to calculate the flat pattern of the helix.

[HEAVY METAL]

there is going to be 72 helical slots evenly spaced around roll. about .09 deep. the roll acts like a cutter for cookie dough . the 3.125 lead is where the slot would end from the start i think. does that make more sense.

[LNDCAD]

I am not sure I understand. Could you e-mail a print or sketch including the helix note?

[mayday]

Im guessing, somfin like this ???

 

 

 

 

N7 G0 G90 G54 X0. Y0. A0. S750 M3

N9 G43 H16 Z12.1

N11 M8

N13 G1 Z12. F8.

N15 X1.3289 Z11.9989 A-1.101

N17 X2.6577 Z11.9956 A-2.203

N19 X3.9866 Z11.99 A-3.303

N21 X5.3154 Z11.9823 A-4.402

N23 X6.6443 Z11.9723 A-5.499

N25 X7.9732 Z11.9601 A-6.595

N27 X9.302 Z11.9457 A-7.687

N29 X10.6309 Z11.9292 A-8.778

N31 X11.9597 Z11.9104 A-9.864

N33 X13.2886 Z11.8895 A-10.948

N35 X14.6175 Z11.8663 A-12.027

N37 X15.9463 Z11.841 A-13.101

N39 X17.2752 Z11.8136 A-14.171

N41 X18.604 Z11.784 A-15.236

N43 X19.9329 Z11.7522 A-16.295

N45 X21.2617 Z11.7184 A-17.348

N47 X22.5906 Z11.6824 A-18.394

N49 X23.9195 Z11.6443 A-19.434

N51 X25.2483 Z11.6041 A-20.467

N53 X26.5772 Z11.5619 A-21.492

N55 X27.906 Z11.5176 A-22.509

N57 X29.2349 Z11.4713 A-23.518

N59 X30.5638 Z11.4229 A-24.518

N61 X31.8926 Z11.3726 A-25.509

N63 X33.2215 Z11.3202 A-26.49

N65 X34.5503 Z11.2659 A-27.462

N67 X36. Z11.2044 A-28.511

[HEAVY METAL]

thats it mayday . so you figured 28.511 deg of rotation . to get the 3.125 lead

[mayday]

if you want the file I made I'll send it to ya in the morning. I just thru a quick axis sub toolpath on it to get the rotation

[HEAVY METAL]

yea i would be interested in how you programmed in mc. i plan to do it at the control with like a few lines of code then a sub routine. also y does the a move. i would think just a axis and x axis

 

thanks mayday

[HEAVY METAL]

lndcad the file is on its way

 

thanks heavy

[HEAVY METAL]

trying to do a toolpath by using axis sub. 2.9856 is the distance i figured in y for my contour. a line start of X0 Y0 to X36 Y 2.9856. i came up with tihs figure by un rolling the 3.125 lead on a 12 dia. did a verify and does not look right . 5.732 is the distance from center to bottom of key. i also off set line 1.38 from center because this is what they call out plus another 1/2 for 1/2 the cutter dia. they want a land of .125 width between grooves. looks like i got my figures wrong or they do. like an opinion

 

thanks heavy

[HEAVY METAL]

trying to do a toolpath by using axis sub. 2.9856 is the distance i figured in y for my contour. a line start of X0 Y0 to X36 Y 2.9856. i came up with tihs figure by un rolling the 3.125 lead on a 12 dia. did a verify and does not look right . 5.732 is the distance from center to bottom of key. i also off set line 1.38 from center because this is what they call out plus another 1/2 for 1/2 the cutter dia. they want a land of .125 width between grooves. looks like i got my figures wrong or they do. like an opinion

 

thanks heavy

[LNDCAD]

You have mail.