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Fadal Post error


Santa Fe
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I'm having this error: "Helical move too short N=" After some try and error; I figure it is the Z movement in the G02 and G03 lines. I already tried by turning thr filter off, but it didn't work. This is a sample of the code that I'm getting.

 

===============================

N38 S6000 M3

N40 H02 Z2. M08

N42 Z.1

N44 G17 G1 Z-.00844 F20.

N46 G2 X-1.0534 Y-.7193 Z-.0084 I-.344 J-.5337 F45.

N48 G1 X-.63499 Y-.71933 Z-.00844

N50 Y-.635

N52 X-1.15804

N54 X-1.22819 Y-.73851

N56 G2 X-1.1085 Y-.8443 Z-.0084 I-.2738 J-.4302

N58 G1 X-.50999 Y-.84433 Z-.00844

N60 Y-.51

N62 X-1.40366

N64 Y-.66373

N66 G2 X-1.3974 Y-.6653 Z-.0084 I-.4771 J-1.9465

N68 X-1.2282 Y-.7385 I-.1356 J-.5453

========================================

 

As you can see my G02 and G03 lines contain Z movements. How can I get rid of them by modifying my post processor or any other method is fine as long as it works.

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See if this switch is available in your post

 

code:

helix_arc   : 1     #Support helix arc output, 0=no, 1=all planes, 2=XY plane only

set it to 2

 

If you applied Thad's Sticky, we might have known that out of the gate

 

biggrin.gifbiggrin.gifbiggrin.gif

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Correct me if im wrong but isn't g17=xy ,g18=zx and, g19=yz. A helical move is possible by programming the linear axis that is not in the selected plain. This third axis is interpolated along the specified axis in a linear manner as the other two axis are moved in the circular motion. the speed of each axis is controlled so that the helical rate matches the feed rate. Are you trying to do a helical for cutting threads or,is it for an arc at a corner in a pocket or,for an external contour. What machine are you using. S.Hall

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Sorry, I should have realized youre NOT cutting threads based upon the g2 commands in the post. I will also ask, Why do you have the I and,J both set as negative values. That is not correct usage of the code. as, the movement towards the final quadrant specifies which code receives negative value through the (incremental) move which is what a g2 or g3 is. If you start your arc from quadrant 1 in g2 CCW. I=/.344 j=/-.5337 as it is moving toward quadrant 4 where as X or I=+ and,Y or J= -

 

 

 

 

x-y+ | X+y+

...............

 

x-y- | x+y-

 

 

 

 

Hope this helps. S Hall

 

[ 07-07-2006, 06:35 AM: Message edited by: S.Hall ]

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Correct me if im wrong but isn't g17=xy ,g18=zx and, g19=yz. A helical move is possible by programming the linear axis that is not in the selected plain. This third axis is interpolated along the specified axis in a linear manner as the other two axis are moved in the circular motion. the speed of each axis is controlled so that the helical rate matches the feed rate.Is it for an arc at a corner in a pocket or,for an external contour. S.Hall

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