Inconel 718

[rightback]

2.5' deep pockets r.52" in the corners

 

any suggestions for cutters and machining meathods?

[robk]

Can you use ceramics?

[Mic6]

...Brutal

[shazam/TPP]

2.5 feet or inches?

[jeff]

quote:

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r.52" in the corners

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is that radius where the walls meet each other or where the floor meets the wall?

[rightback]

walls and sorry thats 2.5" deep

[rightback]

I don't think they are going to spring for ceramics as this is a one of prototype.

[Charlie Pierson]

edm ??

 

Lots of TiAln coated carbide endmills, cut dry or w/ air blast.

[robk]

quote:

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Lots of TiAln coated carbide endmills, cut dry or w/ air blast.

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I disagree... Use coolant, lots of coolant. Cobalt might work better, but you may want to try trochoidal mill method with a good quality solid carbide cutter like Kennametal HARVI, or Hanita Varimill.

 

I would still prefer to use ceramics, probably cheaper in the long run depending on the size of the pocket. This is my recommendation for ceramics.

1.00" Excelerator Mill from Greenleaf using Sandvik inserts (RPGN090300E grade 6060 (non whisker work better then whisker for milling)

We are limited to 10K on our spindles so we're running @ 2600 SFM and .005 IPT with DOC of .040". No problem lasting 4 minutes in the cut. If you have more RPMs' on your spindle then I would go @ least 3500sfm and maybe as far as 5000sfm.... Oh, and milling with ceramics you must run dry

[Goldorak]

send it here , EZ stuff

 

 

3/4 niagara stabilizer HT series + dynamic mill will cut this very easily

[Greg_J]

Drill out your corners first Then use a insert drill (quad, u-drill), as big as you have, drill a hole so your cutter can plunge there. Then use a high feed cutter and create a pocket program with the high feed method using a large radius value in the corner rounding. Then pick the corners.

 

For regular tooling use lots of coolant, things go bad when it gets hot. Milling i used 100 sfpm .008-.0015 fpt ball park, that's what I use for 925. Doc you can go deep it's not a big deal.

 

My .02$.

 

HTH