Haas Lathe macro problem

[pip]

The company a friend works for, has bought a Haas lathe. They had only fanuc controlls before this, so this macro problem never apeared.  Is there a solution for this on a haas..  you cannot program a known position approach with "A"  you cannot use an "A" on the same line as "x" and "Z" ..  hope you can see what I am trying to do.. Starting on the face of a part drive along at A90 to unknown point then drive to a given point at A60. there by letting the controll determin where the intersection point is..

 

code

 

G42G1X[#4-1]Z-[#13-0.2]
G1A90
G1X[#3-[2*[#13-0.15]]]Z0.15A60
G1G40Z2

 

hope somebody can help. 

[Matthew Hajicek - Singularity]

Is the A axis (spindle I presume) positioning only?  The control may not be able to move the A and another axis at the same time.

[mkd]

What would the "a" be referring to on a Fanuc or Haas lathe???

Assuming you are face milling, wouldn't you be talking about the "C" axis?

[SlaveCam]

Dunno about A-axis, but I'm assuming you meant C-axis. (A in some cases refer to a live tool aligned with X-axis) Are you trying to do face contouring? You should check if the control supports G12.1 and G13.1. With it, you can enter Y-coordinates using the C register and what's best, G41 and G42 works in that mode!

[pip]

 

hope this explains better.

[Rocketmachinist]

What machine is this suppose to be. Haas doesnt have an a axis. They have a x z and c axis. The a axis you see on the controller will be for the live tool spindle load meter

 

Sent from my SM-G930T using Tapatalk

 

 

[SlaveCam]

Fanuc indeed does not support specifying angles in linear interpolation, as far as I know, like Siemens does (our controls support chamfer and radius, but naturally they are options...like everything else in Fanuc...) You have to use trigonometry, and in this case, the TAN macro B function. It's nothing but elementary school math

[Rocketmachinist]

http://www.productivity.com/wp-content/uploads/2015/04/Haas-Lathe-Programming-Manual.pdf

[pip]

all the fanuc lathes I have worked on do support this intersection function..

[crazy^millman]

all the fanuc lathes I have worked on do support this intersection function..

 

That is Fanuc this is a HAAS it doesn't work the same. Will have to change the macro to work on the HAAS.

[pip]

I was dreading that answer Ron Branch..  The person who wrote these macros had not structure to his programs..  Oh well, reprogram it is then..

[crazy^millman]

I was dreading that answer Ron Branch..  The person who wrote these macros had not structure to his programs..  Oh well, reprogram it is then..

 

What doesn't kill harm you makes you stronger. :turned: :scooter:

 

Edited to be sensitive.

Edited June 20, 2016 by 5th Axis Consulting Group

[SlaveCam]

If you know the starting points of the lines and their angles, you need a ray-ray intersection macro. The angles must be converted to direction vectors first.

 

The math: http://stackoverflow.com/questions/2931573/determining-if-two-rays-intersect

Example:
First point p1=(X10,Y10), angle=240
Second point p2=(X5,-Y10), angle=90

240 degrees direction vector d1=(cos(240),sin(240))=(X-0.5,Y-0.866)
90 degrees direction vector d2=(cos(90),sin(90))=(X0,Y1)

The first ray p1+x1*d1
The second ray is p2+x2*d2
The intersection is where p1+x1*d1=p2+x2*d2

p1.x+x1*d1.x=p2.x*x2+d2.x
p1.y+x1*d1.y=p2.y*x2+d2.y
you will finally get =>
x1=((p2.y-p1.y)*d2.x-(p2.x-p1.x)*d2.y)/(d2.x*d1.y-d2.y*d1.x)=10
x2=((p2.y-p1.y)*d1.x-(p2.x-p1.x)*d1.y)/(d2.x*d1.y-d2.y*d1.x)=11.34

When you plug these x1 and x2 into the first and second ray formulas, you will get the intersection point at (X5,Y1.34). Of course, the macro should check that they intersect at all (x1 and x2 positive) and they are not parallel (division by zero).

 

Happy writing
 

[Matthew Hajicek - Singularity]

If you want something to debug your macros in try NCPlot.  Free trial period, supports two axis lathe, four axis mill, macros, work offsets, etc.